 | | | Counting objects in a room | Counting objects in a room 2003-12-07 - By Atm
Back
Ok list. Its time to learn :-p
I was just piddling with this and want to learn how to make the
code count the number of objects (that match the argument)
and display it to the character (i know, this function is kind-of
useless but its a way for me to understand the code better)
I also know that this function is missing a chunk of code or two ;)
All im asking for is a gentle kick or shove in the right direction, maybe
some chunks of the exsisting code to look at :)
Flames, help, ect are welcome.
void do_objroom(CHAR_DATA *ch, char *argument )
{
char buf[MIL];
OBJ_DATA *obj;
OBJ_INDEX_DATA *pObjIndex;
int nMatch = 0;
int count = 0;
char arg[MSL];
if ( argument[0] == '\0' )
{
send_to_char( "You can't count nothing?\n\r", ch );
return;
}
if ( IS_NPC(ch) )
stc("Yeah, Whatever.\n\r", ch);
return;
/* insert code that counts the number *
* of (argument) that are in the room */
obj->short_descr = arg;
sprintf(buf,
"This room has (%d)%s in it\n\r",
count, arg);
stc(buf,ch);
return;
}
--
Atm of Forgotten Empire!
__ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ___
McAfee VirusScan Online from the Netscape Network.
Comprehensive protection for your entire computer. Get your free trial today!
http://channels.netscape.com/ns/computing/mcafee/index.jsp?promo=393397
Get AOL Instant Messenger 5.1 free of charge. Download Now!
http://aim.aol.com/aimnew/Aim/register.adp?promo=380455
--
ROM mailing list
ROM@(protected)
http://www.rom.org/cgi-bin/mailman/listinfo/rom
Earn $52 per hosting referral at Lunarpages.
|
|
|